document.write( "Question 129835: Two towns are 243 miles apart. Bob and Joe each start in on of the towns at 12:00 PM and drive towards each other with uniform motion. Bob drives 45mph, joe drives 65 mph. When do they meet (at what time)? WHERE do they meet? \n" ); document.write( "
Algebra.Com's Answer #94806 by solver91311(24713)\"\" \"About 
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Remember \"d=rt\", so \"t=d%2Fr\".\r
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\n" ); document.write( "\n" ); document.write( "Since we are interested in when and where they meet, their drive times must be equal.\r
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\n" ); document.write( "\n" ); document.write( "Let's say that x is the distance Bob drives at 45 mph. That means that the distance Joe drives at 65 mph is 243 - x.\r
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\n" ); document.write( "\n" ); document.write( "Using \"t=d%2Fr\", Bob's drive time is \"t=x%2F45\", and Joe's drive time is \"t=%28243-x%29%2F65\". But we already determined that these drive times are equal so we can say:\r
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\n" ); document.write( "\n" ); document.write( "\"x%2F45=%28243-x%29%2F65\"\r
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\n" ); document.write( "\n" ); document.write( "Cross multiply:
\n" ); document.write( "\"65x=45%28243-x%29\"
\n" ); document.write( "\"65x=10935-45x\"
\n" ); document.write( "\"110x=10935\"\r
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\n" ); document.write( "\n" ); document.write( "From here on out, '=' means 'approximately equal to'\r
\n" ); document.write( "\n" ); document.write( "\"x=99.41\", or Bob drove \"99.41\" miles to the meeting point.\r
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\n" ); document.write( "\n" ); document.write( "Since we know that \"t=d%2Fr\", Bob's travel time must be \"t=99.41%2F45\" or \"t=2.21\" hours. \".21\" hours is \".21+%2A+60=12.6\" minutes, and since they started at straight up noon, they must have met at 2:12.6 PM, and they met 99.41 miles from Bob's starting point.\r
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\n" ); document.write( "\n" ); document.write( "Check:\r
\n" ); document.write( "\n" ); document.write( "Since they met at 99.41 miles from Bob's starting point, they must have met 243 - 99.41 = 143.59 miles from Joe's starting point. If Joe travelled for 2.21 hours at 65 mph, he travelled \"2.21+%2A+65+=+143.59\" miles. Answer checks. (Actually, if you just plug in the numbers given, the calculator shows a bit of error, but if you do the arithmetic from the beginning on the calculator and never round off until the end, it all comes out correctly)
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