document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=129781>Question 129781</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A man travels regularly between two cities . He takes 14/3hours , if he travels at his usual speed . He finds that if he increases his speed by 3km/h , he can reduce           the time by 1/3 hour . What is his usual speed ? <BR>\n" );
document.write( "Pls help         </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #94796 by </B><A HREF=/tutors/aboutme.mpl?userid=test101><B>test101(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=test101><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=94796\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let usual speed = x<BR>\n" );
document.write( "So, 14/3x----------1<BR>\n" );
document.write( "(14/3-1/3)(x+3)----2<BR>\n" );
document.write( "14/3x=(13/30x+3<BR>\n" );
document.write( "1/3x=13<BR>\n" );
document.write( "x=13X3(by cross-multiplication)<BR>\n" );
document.write( "x=39 Km/h<BR>\n" );
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