document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=129781>Question 129781</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A man travels regularly between two cities . He takes 14/3hours , if he travels at his usual speed . He finds that if he increases his speed by 3km/h , he can reduce           the time by 1/3 hour . What is his usual speed ? <BR>\n" );
document.write( "Pls help         </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #94776 by </B><A HREF=/tutors/aboutme.mpl?userid=oscargut><B>oscargut(2103)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oscargut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=oscargut><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=94776\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x the usual speed\r<BR>\n" );
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document.write( "then (14/3)x=(14/3-1/3)(x+3)\r<BR>\n" );
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document.write( "then (14/3)x=(13/3)x+13<BR>\n" );
document.write( "then (1/3)x=13 then x=39\r<BR>\n" );
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document.write( "R: x= 39 km/h </SPAN>\n" );
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