document.write( "Question 129729This question is from textbook intermediate algebra
\n" ); document.write( ": 1. Find the slope of the line that passes through the points (-4, 1) and (3, 8).\r
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Algebra.Com's Answer #94765 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Let's denote the first point (-4,1) as . In other words, and \r
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\n" ); document.write( "\n" ); document.write( "Now let's denote the second point (3,8) as . In other words, and \r
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\n" ); document.write( "\n" ); document.write( "\"m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29\" Start with the slope formula\r
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\n" ); document.write( "\n" ); document.write( "\"m=%288-1%29%2F%283--4%29\" Plug in \"y%5B2%5D=8\",\"y%5B1%5D=1\",\"x%5B2%5D=3\",\"x%5B1%5D=-4\"\r
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\n" ); document.write( "\n" ); document.write( "\"m=7%2F7\" Subtract the terms in the numerator \"8-1\" to get \"7\". Subtract the terms in the denominator \"3--4\" to get \"7\"\r
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\n" ); document.write( "\n" ); document.write( "\"m=1\" Reduce\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the slope of the line through the points (-4,1) and (3,8) is \"m=1\"
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