document.write( "Question 129775This question is from textbook Fundamentals of mathematics
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document.write( ": one card is randomly selected from a shuffled standard deck of 52 cards and then a die is rolled. find the probility of obtaining
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document.write( "a. a red card and a 1
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document.write( "b. a red card or a 1
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document.write( "c. a picture card and a 1
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document.write( "d. a picture card or a 1
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document.write( "e. a red picture card and a 1
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document.write( "f. a red picture card or a 1 \n" );
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Algebra.Com's Answer #94759 by stanbon(75887) ![]() You can put this solution on YOUR website! one card is randomly selected from a shuffled standard deck of 52 cards and then a die is rolled. find the probility of obtaining \n" ); document.write( "a. a red card and a 1= P(red)*P(1) = 1/4*1/6 = 1/24 \n" ); document.write( "because these are independent events. \n" ); document.write( "------------------------------------ \n" ); document.write( "b. a red card or a 1 = P(red) + P(1) = 1/4 + 1/6 = 10/24 = 5/12 \n" ); document.write( "because these are mutually exclusive events. \n" ); document.write( "----------------------------------- \n" ); document.write( "c. a picture card and a 1 = P(picture)*P(1) = 12/52 * 1/6 = 1/26 \n" ); document.write( "because these are independent events. \n" ); document.write( "-------------------------------------- \n" ); document.write( "d. a picture card or a 1 = P(picture) or P(1) = 12/52 + 1/6 = 58/(52*6)= 29/156 \n" ); document.write( "because these are mutually exclusive events \n" ); document.write( "--------------------------------------- \n" ); document.write( "e. a red picture card and a 1 = P(red picture)*P(1) = 6/52*1/6 = 1/52 \n" ); document.write( "independent events \n" ); document.write( "------------------- \n" ); document.write( "f. a red picture card or a 1 = P(red pic)+P(1) = 6/52 + 1/6= 88/[52*6] = 11/39 \n" ); document.write( "---------------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |