document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=129766>Question 129766</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A sum of $3,500 is invested in two parts. One part brings a return of 5% and the other a return of 8%. The total annual return is $250. Find the amount invested at each rate. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #94749 by </B><A HREF=/tutors/aboutme.mpl?userid=oscargut><B>oscargut(2103)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oscargut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=oscargut><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=94749\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A sum of $3,500 is invested in two parts. One part brings a return of 5% and the other a return of 8%. The total annual return is $250. Find the amount invested at each rate. <BR>\n" );
document.write( "Let C1 the amount invested at 5% and C2 the amount invested at 8% then <BR>\n" );
document.write( "C1 + C2 =3500 and C1(0,05)+C2(0,08)=250 then C2=(3500-C1) then<BR>\n" );
document.write( "C1(0,05)+(3500-C1)(0,08)=250 then -0,03C1 +280 =250<BR>\n" );
document.write( "then -0,03C1=-30 <BR>\n" );
document.write( "then C1=1000 and C2=2500  </SPAN>\n" );
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