document.write( "Question 129649This question is from textbook Introductory Algebra
\n" ); document.write( ": The problem states that an employer has a daily payroll of $1225 when employing some workers at $80 per day and others at $85 per day. When the number of $80 workers is increased by 50% and the number of $85 workers is decreased by 1/5, the new daily payroll is $1540. How many were originally employed at each rate? \n" ); document.write( "
Algebra.Com's Answer #94688 by checkley71(8403)\"\" \"About 
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80X+85Y=1225 OR 80X=1225-85Y OR X=(1225-85Y)/80
\n" ); document.write( "80(X+.5X)+85(Y-.2Y)=1540
\n" ); document.write( "80*1.5X+85*.8Y=1540
\n" ); document.write( "120X+68Y=1540
\n" ); document.write( "NOW REPLACE X BY (1225-85Y)/80
\n" ); document.write( "120(1225-85Y)/80+68Y=1540
\n" ); document.write( "1.5(1225-85Y)+68Y=1540
\n" ); document.write( "1837.5-127.5Y+68Y=1540
\n" ); document.write( "-59.5Y=1540-1837.5
\n" ); document.write( "-59.5Y=297.5
\n" ); document.write( "Y=-297.5/-59.5
\n" ); document.write( "Y=5 NUMBER OF THE ORIGINAL $85 HOURLY WORKERS.
\n" ); document.write( "X=(1225-85*5)/80
\n" ); document.write( "X=(1225-425)/80
\n" ); document.write( "X=800/80
\n" ); document.write( "X=10 NUMBER OF ORIGINAL $80 HOURLY WORKERS.
\n" ); document.write( "PROOF:
\n" ); document.write( "80*10+5*85=1225
\n" ); document.write( "800+425=1225
\n" ); document.write( "1225=1225 \n" ); document.write( "
\n" );