document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=129665>Question 129665</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two workers can do a job in 33/7 hours.THe first one can do the same job in 6 hours. How much time  will it take for the second one to complete the job if he works  alone ?\r<BR>\n" );
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document.write( "PLZZZ !! DO HELP ME ! I hv an exam tomorrow abd i dont understand this ! If someone helps me than god bless him !! PLZ </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #94682 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=94682\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 6X/(6+X)=33/7 NOW CROSS MULTIPLY.<BR>\n" );
document.write( "6X*7=33(6+X)<BR>\n" );
document.write( "42X=198+33X<BR>\n" );
document.write( "42X-33X=198<BR>\n" );
document.write( "9X=198<BR>\n" );
document.write( "X=22 HOURS FOR THE SECOND WORKER IF HE WORKS ALONE.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "6*22/(6+22)=33/7<BR>\n" );
document.write( "132/28=33/7<BR>\n" );
document.write( "28*33=132*7<BR>\n" );
document.write( "924=924 </SPAN>\n" );
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