document.write( "Question 129663: 3 brothers dispose a sum of money at the bank.The first one disposes 1/2 of the sum, the second 1/5 of the sum and the last one 3/10.After that the first one takes 2/3 of his sum,the second 1/2 of this sum and the last one 5/12 of his sum ,530$ remain in there account. Find :\r
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document.write( "a)What sum of money each brother disposes at the bank ?
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document.write( "b)What sum of money remains in the bank for each brother?\r
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document.write( "PLZZZZZZZZ HELPPPPPPPP FOR GOD SAKEEEEEEE THANKS \n" );
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Algebra.Com's Answer #94660 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! .5X+.2X+.3X=X PERCENTAGE OF THE AMOUNT EACH DEPOSITED. \n" ); document.write( "(2/3).5X+(1/2).2X+(5/12).3X=530 AMOUNT LEFT AFTER THE WITHDRAWELS. \n" ); document.write( "1X/3+.1X+1.5X/12=530 \n" ); document.write( "(4*1X+12*.1X+1.5X)/12=530 \n" ); document.write( "(4X+1.2X+1.5X)/12=530 \n" ); document.write( "6.7/12=530 \n" ); document.write( "6.7=12*530 \n" ); document.write( "6.7X=6360 \n" ); document.write( "X=6360/6.7 \n" ); document.write( "X=949.25 IS THE TOTAL AMOUNT DEPOSITED. \n" ); document.write( "949.25*.5=474.625 AMOUNT DEPOSITED BY THE FIRST BROTHER. \n" ); document.write( "949.25*.2=189.85 AMOUNT DEPOSITED BY THE SECOND BROTHER. \n" ); document.write( "949.25*.3=284.775 AMOUNT DEPOSITED BY THE THIRD BROTHER. \n" ); document.write( "474.625*2/3=316.42 FIRST BROTHER REMAINING FUNDS. \n" ); document.write( "189.85*1/2=94.92 SECOND BROTHER REMAINING FUNDS. \n" ); document.write( "284.775*5/12=118.66 THIRD BROTHERS REMAINING FUNDS. \n" ); document.write( " |