document.write( "Question 129672This question is from textbook Algebra structure and meathod
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document.write( ": A chemist mixed a 20% acid solution with a 60% acid solution to make 10 L of a 30% solution. How many liters of the 60% solution were used? \n" );
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Algebra.Com's Answer #94659 by stanbon(75887) ![]() You can put this solution on YOUR website! A chemist mixed a 20% acid solution with a 60% acid solution to make 10 L of a 30% solution. How many liters of the 60% solution were used? \n" ); document.write( "---------------- \n" ); document.write( "20% solution DATA: \n" ); document.write( "Amount = x liters; active ingredient = 0.20x L \n" ); document.write( "-------------- \n" ); document.write( "60% solution DATA: \n" ); document.write( "Amount = \"10-x\" liters ; active = 0.60(10-x)= 6-0.6x liters \n" ); document.write( "------------------ \n" ); document.write( "Mixture DATA; \n" ); document.write( "Amt. = 10 L : active = 0.30*10 = 3 liters \n" ); document.write( "---------------------- \n" ); document.write( "EQUATION: \n" ); document.write( "active + active = active \n" ); document.write( "0.2x + 6 - 0.6x = 3 \n" ); document.write( "-0.4x = -3 \n" ); document.write( "x = 7.5 liters (amount of 20% solution needed for the mix) \n" ); document.write( "10-x = 2.5 liters (amount of 60% solution needed for the mix) \n" ); document.write( "======================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |