document.write( "Question 129653: I need to write the slope-intercept form of the equation of the line that is perpendicular to 7x-8y= -2 and contains the point(6,3). I cannot get passed this step: y-3= -8/7(x-6), how do you multiply -8/7 * -6? \n" ); document.write( "
Algebra.Com's Answer #94655 by checkley71(8403)\"\" \"About 
You can put this solution on YOUR website!
FIRST YOU MUST CHANGE THE FORMULA TO A LINE FORMULA OF THE FORM Y=mX+b WHERE m=SLOPE & b=Y INTERCEPT.
\n" ); document.write( "7X-8Y=-2
\n" ); document.write( "-8Y=-7X-2
\n" ); document.write( "Y=-7X/-8-2/-8
\n" ); document.write( "Y=7X/8+1/4 NOW YOU HAVE A SLOPE=7/8 & A Y INTERCEPT=1/4 (RED LINE)
\n" ); document.write( "FOR A LINE TO BE PERPENDICULAR TO THIS LINE IT WILL HAVE A SLOPE = THE NEGATIVE RECIPRICAL OF THIS SLOPE. THUS THE SLOPE=-8/7.
\n" ); document.write( "BECAUSE THIS PERPENDICULAR LINE PASSES THROUGH (6,3) YOU NOW NEED TO REPLACE THE X & Y VALUES IN THE LINE EQUATION WITH THESE VALUES.
\n" ); document.write( "3=-8/7*6+b
\n" ); document.write( "3=-56/7+B
\n" ); document.write( "b=3+56/7
\n" ); document.write( "b=(21+56)/7
\n" ); document.write( "b=77/7
\n" ); document.write( "b=11 ANSWER FOR THE Y INTERCEPT.
\n" ); document.write( "THUS THE EQUATION FOR THIS PERPENDICULAR LINE IS:
\n" ); document.write( "Y=-8X/7+11 (GREEN LINE)
\n" ); document.write( "\"+graph%28+300%2C+200%2C+-10%2C+10%2C+-10%2C+10%2C+7x%2F8+%2B1%2F4%2C+-8x%2F7+%2B11%29+\" (graph 300x200 pixels, x from -10 to 10, y from -10 to 10, of TWO functions 7x/8 +1/4 and -8x/7 +11). \n" ); document.write( "
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