document.write( "Question 129625: translate to an algebraic equation then solve. the lenght of a rectangle is six units longer than the width. find the lenght and width if the perimeter of the rectangle is 60 units.
\n" ); document.write( "2) fin the circumference and area of a circle with the radius 3.5 feet. use 22/7 for pi.
\n" ); document.write( "3) the width of a rectangular playground is 18 meters less than the lenght. find the width when the perimeter of the rectangle is 84 meters.
\n" ); document.write( "once again thanks a lot this will help me get my ged
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Algebra.Com's Answer #94642 by stanbon(75887)\"\" \"About 
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translate to an algebraic equation then solve. the length of a rectangle is six units longer than the width. find the length and width if the perimeter of the rectangle is 60 units.
\n" ); document.write( "Let width = x units
\n" ); document.write( "Then length = x+6 units
\n" ); document.write( "Perimeter = 2(length + width)
\n" ); document.write( "2(x+(x+6)) = 60
\n" ); document.write( "2x+6 = 30
\n" ); document.write( "2x = 24
\n" ); document.write( "x = 12 units (width)
\n" ); document.write( "x+6 = 18 units (length)
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\n" ); document.write( "2) find the circumference and area of a circle with the radius 3.5 feet. use 22/7 for pi.
\n" ); document.write( "Area = (pi)r^2
\n" ); document.write( "Area = (22/7)*3.5^2 = 22*3.5*3.5/7 = 22*3.5/2 = 11*3.5 = 38.5 sq ft
\n" ); document.write( "-----------------------
\n" ); document.write( "3) the width of a rectangular playground is 18 meters less than the lenght. find the width when the perimeter of the rectangle is 84 meters.
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\n" ); document.write( "Let the length be \"x meters; the width is \"x-18\" meters.
\n" ); document.write( "Perimeter = 2(length + width)
\n" ); document.write( "84 = 2(x + x-18)
\n" ); document.write( "2x-18 = 42
\n" ); document.write( "2x = 60
\n" ); document.write( "x = 30 meters (length)
\n" ); document.write( "x-18 = 12 meters (width)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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