document.write( "Question 129612: Tom is building a rectangular dog pen that we wants to enclose. The width of the pen is 2 yards less than the length. If the area of dog pen is 15 square yards, hpw many yards of fence would he need to completely enclose the pen? Please and thank you :) \n" ); document.write( "

Algebra.Com's Answer #94635 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Width = $\"w\"$ yds and length= $\"l\"$ yds
\n" ); document.write( " $\"l+=+w+%2B+2\"$
\n" ); document.write( "Area = 15 yds2
\n" ); document.write( "Area = $\"w%2Al\"$
\n" ); document.write( "15 = $\"w%28w+%2B+2%29\"$
\n" ); document.write( " $\"w%5E2+%2B+2w+=+15\"$
\n" ); document.write( " $\"w%5E2+%2B+2w+-+15+=+0\"$
\n" ); document.write( " $\"%28w+-+3%29%28w+%2B+5%29+=+0\"$
\n" ); document.write( " $\"w+=+3\"$
\n" ); document.write( " $\"w+=+-5\"$ can't used a negative, reject
\n" ); document.write( "The perimeter would be
\n" ); document.write( " $\"w+%2B+w+%2B+%28w+%2B+2%29+%2B+%28w+%2B+2%29\"$
\n" ); document.write( " $\"2w+%2B+2w+%2B+4\"$
\n" ); document.write( " $\"4w+%2B+4\"$
\n" ); document.write( " $\"4%2A3+%2B+4\"$
\n" ); document.write( " $\"16\"$ yds
\n" ); document.write( "He will need 16 yds of fence
\n" ); document.write( " \n" ); document.write( "

\n" );