document.write( "Question 129616This question is from textbook
\n" ); document.write( ": solve.
\n" ); document.write( "Donna is late for a sales meeting after traveling from one town to another at a speed of 32 mph. If she had tarveled 4 mph faster, she could have made the trip in 1/2 hr less time. How far apart are the towns? \n" ); document.write( "

Algebra.Com's Answer #94633 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"d\"$ = the distance apart
\n" ); document.write( "Let $\"t\"$ = her actual time
\n" ); document.write( " $\"d+=+32t\"$
\n" ); document.write( " $\"d+=+36%28t+-+.5%29\"$
\n" ); document.write( " $\"32t+=+36%28t+-+.5%29\"$
\n" ); document.write( " $\"32t+=+36t+-+18\"$
\n" ); document.write( " $\"4t+=+18\"$
\n" ); document.write( " $\"t+=+4.5\"$
\n" ); document.write( " $\"d+=+32%2At\"$
\n" ); document.write( " $\"d+=+32%2A4.5\"$
\n" ); document.write( " $\"d+=+144\"$ mi
\n" ); document.write( "The towns are 144 mi apart
\n" ); document.write( "check answer:
\n" ); document.write( " $\"d+=+32t\"$
\n" ); document.write( " $\"d+=+36%28t+-+.5%29\"$
\n" ); document.write( " $\"144+=+32t\"$
\n" ); document.write( " $\"t+=+4.5\"$
\n" ); document.write( " $\"144+=+36t+-+18\"$
\n" ); document.write( " $\"36t+=+162\"$
\n" ); document.write( " $\"t+=+4.5\"$
\n" ); document.write( "OK \n" ); document.write( "

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