document.write( "Question 129531: A band has been drawing average crowds of 500 people. It is thought that for every $1 increase in the $12 ticket price, the average attendence will decrease by 50. At what ticket price will the nightly receipts be $5600? \n" ); document.write( "

Algebra.Com's Answer #94594 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"n\"$ = the number of $1 ticket increases
\n" ); document.write( " $\"12+%2B+n\"$ is the ticket price
\n" ); document.write( " $\"50n\"$ is the decrease in attendence for each $1
\n" ); document.write( "increase in ticket price
\n" ); document.write( " $\"500+-+50n\"$ is the attendence for each $1
\n" ); document.write( "increase in ticket price
\n" ); document.write( " $\"%28500+-+50n%29%2812+%2B+n%29+=+5600\"$
\n" ); document.write( " $\"6000+-+600n+%2B+500n+-+50n%5E2+=+5600\"$
\n" ); document.write( "subtract 5600 from both sides
\n" ); document.write( " $\"400+-+600n+%2B+500n+-+50n%5E2+=+0\"$
\n" ); document.write( "Multiply both sides by $\"-1\"$
\n" ); document.write( " $\"-400+%2B+600n+-+500n+%2B+50n%5E2+=+0\"$
\n" ); document.write( " $\"50n%5E2+%2B+100n+-+400+=+0\"$
\n" ); document.write( "divide both sides by $\"50\"$
\n" ); document.write( " $\"n%5E2+%2B+2n+-+8+=+0\"$
\n" ); document.write( " $\"%28n+%2B+4%29%28n+-+2%29\"$
\n" ); document.write( " $\"n+=+-4\"$
\n" ); document.write( " $\"n+=+2\"$
\n" ); document.write( " $\"12+%2B+n\"$ is the ticket price
\n" ); document.write( "The nightly receipts are $5600 when the ticket
\n" ); document.write( "price is $14
\n" ); document.write( "check answer:
\n" ); document.write( " $\"%28500+-+50n%29%2812+%2B+n%29+=+5600\"$
\n" ); document.write( " $\"500+-+50%2A2%29%2812+%2B+2%29+=+5600\"$
\n" ); document.write( " $\"400%2A14+=+5600\"$
\n" ); document.write( " $\"5600+=+5600\"$
\n" ); document.write( "OK
\n" ); document.write( " \n" ); document.write( "

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