document.write( "Question 129509: One-half of Mr. Staines' age four years from now minus three-fourths of Mr. Staines' age four years ago is zero. What is Mr. Staines' present age? \n" ); document.write( "
Algebra.Com's Answer #94585 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! Let x=Mr. Staine's present age\r \n" ); document.write( "\n" ); document.write( "x+4=his age 4 years from now and \n" ); document.write( "x-4=his age 4 years ago\r \n" ); document.write( "\n" ); document.write( "Now we are told that:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(1/2)(x+4)-(3/4)(x-4)=0 simplify\r \n" ); document.write( "\n" ); document.write( "(x/2)+2-(3x/4)+3=0 multiply each term by 4\r \n" ); document.write( "\n" ); document.write( "2x+8-3x+12=0 or \n" ); document.write( "-x+20=0 subtract 20 from each side\r \n" ); document.write( "\n" ); document.write( "-x=-20 divide both sides by -1 \n" ); document.write( "x=20-------------------------------------Mr. Staine's present age\r \n" ); document.write( "\n" ); document.write( "CK \n" ); document.write( "(1/2)(20+4)-(3/4)(20-4)=0\r \n" ); document.write( "\n" ); document.write( "12-12=0 \n" ); document.write( "0=0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor \n" ); document.write( " |