document.write( "Question 129509: One-half of Mr. Staines' age four years from now minus three-fourths of Mr. Staines' age four years ago is zero. What is Mr. Staines' present age? \n" ); document.write( "
Algebra.Com's Answer #94585 by ptaylor(2198)\"\" \"About 
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Let x=Mr. Staine's present age\r
\n" ); document.write( "\n" ); document.write( "x+4=his age 4 years from now and
\n" ); document.write( "x-4=his age 4 years ago\r
\n" ); document.write( "\n" ); document.write( "Now we are told that:\r
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\n" ); document.write( "\n" ); document.write( "(1/2)(x+4)-(3/4)(x-4)=0 simplify\r
\n" ); document.write( "\n" ); document.write( "(x/2)+2-(3x/4)+3=0 multiply each term by 4\r
\n" ); document.write( "\n" ); document.write( "2x+8-3x+12=0 or
\n" ); document.write( "-x+20=0 subtract 20 from each side\r
\n" ); document.write( "\n" ); document.write( "-x=-20 divide both sides by -1
\n" ); document.write( "x=20-------------------------------------Mr. Staine's present age\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "(1/2)(20+4)-(3/4)(20-4)=0\r
\n" ); document.write( "\n" ); document.write( "12-12=0
\n" ); document.write( "0=0\r
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\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor
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