document.write( "Question 129512: Five hundred gallons of 82-octane gasoline is obtained by mixing 80-octane gasoline with 86-octane gasoline. How much of each must be used? \n" ); document.write( "
Algebra.Com's Answer #94577 by checkley71(8403)\"\" \"About 
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.86X+.80(500-X)=.82*500
\n" ); document.write( ".86X+400-.80X=410
\n" ); document.write( ".06X=410-400
\n" ); document.write( ".06X=10
\n" ); document.write( "X=10/.06
\n" ); document.write( "X=166 2/3 GALLONS OF 86 OCTAIN IS USED.
\n" ); document.write( "500-166 2/3=333 1/3 GALLONS OF 80 OCTAIN IS USED.
\n" ); document.write( "PROOF
\n" ); document.write( ".86*166.67+.80*333.33=.82*500
\n" ); document.write( "143.34+266.66=410
\n" ); document.write( "410=410
\n" ); document.write( "
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