document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=129409>Question 129409</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you help me with a substitution problem? I am still getting confused,usually with the second part of the problem.It's not in a book.I do not think there is a solution for both of them to make them come out correctly.I really need simple step by step help in order to learn how to do them on my own.Can I just plug each of the sets of numbers given? Your help is greatly appreciated. .The problem is:\r<BR>\n" );
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document.write( "         x=2y-8         3x-2y= -12  \r<BR>\n" );
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document.write( "The choices were: a)2,-3 b)0,4 c)-4,4 d)-2,3 e)none<BR>\n" );
document.write( "I CHOSE E - none of them (I almost chose C) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #94541 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=94541\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> X=2Y-8<BR>\n" );
document.write( "3X-2Y=-12<BR>\n" );
document.write( "3(2Y-8)-2Y=-12<BR>\n" );
document.write( "6Y-24-2Y=-12<BR>\n" );
document.write( "4Y=-12+24<BR>\n" );
document.write( "4Y=12<BR>\n" );
document.write( "Y=12/4<BR>\n" );
document.write( "Y=3 ANSWER.<BR>\n" );
document.write( "X=2*3-8<BR>\n" );
document.write( "X=6-8<BR>\n" );
document.write( "X=-2 ANSWER.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "3*-2-2*3=-12<BR>\n" );
document.write( "-6-6=-12<BR>\n" );
document.write( "-12=-12 </SPAN>\n" );
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