document.write( "Question 129411: I tried a substitution problem on my own.I am tryng my best .I do not think I did it the proper way but I think I have the answer and I would like your opinion and help if I got it wrong.Please.The problem is:\r
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document.write( " x-4y=5
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document.write( " x-2y=1\r
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document.write( " The answer I got is -3,-2. Is this correct? \r
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document.write( " Thankyou \n" );
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Algebra.Com's Answer #94540 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! X-4Y=5 \n" ); document.write( "-X+2Y=-1 \n" ); document.write( "----------------------------- \n" ); document.write( "-2Y=4 \n" ); document.write( "Y=4/-2 \n" ); document.write( "Y=-2 ANSWER. \n" ); document.write( "X-4*-2=5 \n" ); document.write( "X+8=5 \n" ); document.write( "X=5-8 \n" ); document.write( "X=-3 (-3,-2) IS THE CORRECT ANSWER. \n" ); document.write( "-(-3)+2(-2)=-1 \n" ); document.write( "3-4=-1 \n" ); document.write( "-1=-1 \n" ); document.write( "----------------------------------------------------------- \n" ); document.write( "As I stated earlier, I thank you very much. Do you feel like helping me do another for the \n" ); document.write( "road. The problem is: 5x+2y =7 x-y = 0 \n" ); document.write( "--------------------------------- \n" ); document.write( "x-y or x=y \n" ); document.write( "5*y+2y=7 \n" ); document.write( "5y+2y=7 \n" ); document.write( "7y=7 \n" ); document.write( "y=7/7 \n" ); document.write( "y=1 answer. \n" ); document.write( "x=1 answer.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |