document.write( "Question 129418: I need help with this question\r
\n" ); document.write( "\n" ); document.write( "Suppose $10,000 is invested at an annual rate of 5% for 10 years. I need to find the future value if interest is compounded as follows: \r
\n" ); document.write( "\n" ); document.write( "a) quarterly\r
\n" ); document.write( "\n" ); document.write( "b) monthly\r
\n" ); document.write( "\n" ); document.write( "c) daily (365 days) \n" ); document.write( "
Algebra.Com's Answer #94538 by checkley71(8403)\"\" \"About 
You can put this solution on YOUR website!
P(1+R/n)^nT P=PRINCIPAL, R=RATE, N= NUMBER OF PERIODS PER YEAR, T=NUMBER OF YEARS.
\n" ); document.write( "A) 10,000(1+.05/4)^4*10
\n" ); document.write( "10,000(1+.0125)^40
\n" ); document.write( "10,000(1.0125)^40
\n" ); document.write( "10,000*1.6436
\n" ); document.write( "16,436 THE VALUE OF THIS INVESTMENT AFTER 10 YEARS COMPOUNDED QUARTERLY.
\n" ); document.write( "B) 10,000(1+.05/12)^12*10
\n" ); document.write( "10,000(1+.00417)^120
\n" ); document.write( "10,000(1.00417)^120
\n" ); document.write( "10,000*1.6477
\n" ); document.write( "16,477 INVESTMENT AFTER 10 YEARS OF MONTHLY COMPOUNDING.
\n" ); document.write( "C) 10,000(1+.05/365)^365^10
\n" ); document.write( "10,000(1+.0001369)^3650
\n" ); document.write( "10,000(1.0001369)^3650
\n" ); document.write( "10,000*1.648146
\n" ); document.write( "16,481.46 INVESTMENT AFTER 10 YEARS OF DAILY COMPOUNDING.\r
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