document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=129391>Question 129391</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0321205669/algebrahomeworkh>A Survey of Mathematics with Applications</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Mike invested $6000 for one year. He invested part of it at 9% and the rest at 11%. At the end of the year he earned $624 in interest. How much did he invest at each rate? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #94530 by </B><A HREF=/tutors/aboutme.mpl?userid=amine><B>amine(11)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=amine><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=94530\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> we suppose that X is the value invisted by 9%\r<BR>\n" );
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document.write( "then 9%X+11%(6000-X)=624 => 9X-11X+66000=62400 => X=1800 the value invested at 9% and Y=6000-1800=4200 is the value invested at 11% </SPAN>\n" );
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