document.write( "Question 19560: find the solution of the exponential aquation
\n" ); document.write( " 2^1-x = 19
\n" ); document.write( "in ters of logarithms or correct to four decimal places.
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Algebra.Com's Answer #9453 by Earlsdon(6294)\"\" \"About 
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\"2%5E%281-x%29+=+19\" Take the log of both sides.
\n" ); document.write( "\"%281-x%29log2+=+log19\" Divide both sides of the equation by log2
\n" ); document.write( "\"1-x+=+%28log19%29%2F%28log2%29\" Add x to both sides.
\n" ); document.write( "\"1+=+%28log19%29%2F%28log2%29+%2B+x\" Subtract \"%28log19%29%2F%28log2%29\" from both sides.
\n" ); document.write( "\"1+-+%28log19%29%2F%28log2%29+=+x\" Evaluate.
\n" ); document.write( "\"x+=+1+-+4.2479\"
\n" ); document.write( "\"x+=+-3.2479\"\r
\n" ); document.write( "\n" ); document.write( "Check:\r
\n" ); document.write( "\n" ); document.write( "\"2%5E%281-%28-3.2479%29%29+=+2%5E4.2479\" = \"18.9996\"
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