document.write( "Question 129097: Find three consecutive odd numbers such that the sum of their squares is a four-digit number with all four digits the same?
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Algebra.Com's Answer #94431 by edjones(8007)![]() ![]() You can put this solution on YOUR website! Let x, x+2, x+4 be the numbers. \n" ); document.write( "x^2+(x+2)^2+(x+4)^2 \n" ); document.write( "x^2+x^2+4x+4+x^2+8x+16 \n" ); document.write( "3x^2+12x+20=5555 I tried all combinations from 1111 t0 5555 on TI-89 calculator until I got an integer answer for x. \n" ); document.write( "3x^2+12x-5535=0 \n" ); document.write( "3(x^2+4x-1845)=0 \n" ); document.write( "x^2+4x =1845 \n" ); document.write( "x^2+4x+4=1845+4 Complete the square. \n" ); document.write( "(x+2)^2=1849 \n" ); document.write( "x+2=+-43 \n" ); document.write( "x=-2+-43 \n" ); document.write( "x=-45, x=41 (-45 is extraneous.) \n" ); document.write( "x=41 \n" ); document.write( "The numbers are 41,43,45 \n" ); document.write( ". \n" ); document.write( "Check: \n" ); document.write( "41^2+43^2+45^2 \n" ); document.write( "=1681+1849+2025 \n" ); document.write( "=5555 \n" ); document.write( ". \n" ); document.write( "Ed\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |