document.write( "Question 129139: Hi there hows it going? I was wondering if you would be able to assist me please. I am stuck on how to work out a word problem, regarding a rectangle. It goes like this: The perimeter of a rectangular field is 184m, and its area is 1920m^2. Find the dimensions of the recangle.
\n" ); document.write( "I have worked out that the dimensions are in fact 32m x 60m = 1920m^2, or (32 x 2) + (60 x 2) = 184m. However what I need to know is how to work this out with a formular as I will not always have an entire hour to muck around. Your help would be greatly appreciated. Cheers D. \n" ); document.write( "

Algebra.Com's Answer #94429 by edjones(8007) $\"\"$ $\"About$

You can put this solution on YOUR website!
2L+2w=184
\n" ); document.write( "L*w=1920
\n" ); document.write( ".
\n" ); document.write( "L=1920/w
\n" ); document.write( "2(1920/w)+2w=184 Substitute 1920/w for L
\n" ); document.write( "3840/w+2w=184
\n" ); document.write( "3840+2w^2=184w multiply each side by x to eliminate fractions.
\n" ); document.write( "2w^2-184w+3840=0
\n" ); document.write( "2(w^2-92+1920)=0
\n" ); document.write( "w^2-92+2116=-1920+2116 complete the square
\n" ); document.write( "(w-46)^2=196
\n" ); document.write( "w-46=+-14
\n" ); document.write( "w=46+-14
\n" ); document.write( "w=60, w=32
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\n" ); document.write( "Ed\r
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