document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=129169>Question 129169</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am a bit confused about this problem. I am seeing it as a negative 4 (-4). If anyone can tell me if I have performed this expression correct please let me know, thanks!\r<BR>\n" );
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document.write( "Problem:\r<BR>\n" );
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document.write( "2(a-4)-4(-3-2a)  (I am seeing a negative 4 outside of the parenthesis here on   this first step, am I correct?)\r<BR>\n" );
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document.write( "Answer that I came up with:\r<BR>\n" );
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document.write( "2(a-4)-4(-3-2a)<BR>\n" );
document.write( "2a-8+12+8a<BR>\n" );
document.write( "2.25=a\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #94412 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=94412\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2(A-4)-4(-3-2A)<BR>\n" );
document.write( "2A-8+12+8A<BR>\n" );
document.write( "10A+4<BR>\n" );
document.write( "2(5A+2) ANSWER.<BR>\n" );
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document.write( "WHERE DO YOU GET THE = SIGN? THERE IS NO = SIGN. </SPAN>\n" );
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