document.write( "Question 129145: I have to solve this problem by the addition method. I do have a book but this problem is not out of a book,it's from a handout. I tried to follow the steps in the book to do this but its not clear enough for me.I'm not sure how to go about doing this.Do I just add them together and then plug in numbers that are given? The problem is:\r
\n" ); document.write( "\n" ); document.write( "\"3x%2B4y=1\"
\n" ); document.write( "\"x%2B4y=7\"\r
\n" ); document.write( "\n" ); document.write( "The choice for answers are: A) (3,2) B)(-2,3) C)(3,-2)D)(-3, 5/2) E)(none of them)\r
\n" ); document.write( "\n" ); document.write( "I chose NONE OF THE ABOVE.\r
\n" ); document.write( "\n" ); document.write( "Thankyou so much!
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Algebra.Com's Answer #94399 by Construe(3)\"\" \"About 
You can put this solution on YOUR website!
Edit: \"4y%2B4y\" does not always equal \"0\", but \"4y-4y=0\" always. That is what we are doing when we take Equation 1 minus Equation 2. To illustrate my point, I will show it step-by-step:\r
\n" ); document.write( "\n" ); document.write( "\"%283x%2B4y%29-%28x%2B4y%29=1-7\"\r
\n" ); document.write( "\n" ); document.write( "Simplify the \"1-7\" on the right side of the =.
\n" ); document.write( "\"%283x%2B4y%29-%28x%2B4y%29=-6\"\r
\n" ); document.write( "\n" ); document.write( "Remove unnecessary brackets (or parentheses, depending on what you want to call them).
\n" ); document.write( "\"3x%2B4y-%28x%2B4y%29=-6\"\r
\n" ); document.write( "\n" ); document.write( "Now we remove the other pair of brackets. However, the sign before the open bracket is a minus sign, so we change the + sign inside the bracket to a -.
\n" ); document.write( "\"3x%2B4y-x-4y=-6\"\r
\n" ); document.write( "\n" ); document.write( "To understand why we must change the sign, consider this example. Let x be apples and y be oranges. When I perform \"-%28x%2B4y%29\", I am taking away 1 apple and 4 oranges. That would have the same effect as taking away 1 apple, \"-x\", and then taking away 4 oranges, \"-4y\", so:
\n" ); document.write( "\"-%28x%2B4y%29=-x-4y\"\r
\n" ); document.write( "\n" ); document.write( "We have \"3x%2B4y-x-4y=-6\".\r
\n" ); document.write( "\n" ); document.write( "Rearranging the terms,
\n" ); document.write( "\"3x-x%2B4y-4y=-6\"\r
\n" ); document.write( "\n" ); document.write( "Simplifying x,
\n" ); document.write( "\"2x%2B4y-4y=-6\"\r
\n" ); document.write( "\n" ); document.write( "Obviously +4y and -4y cancel each other out, so our final equation is
\n" ); document.write( "\"2x=-6\"
\n" ); document.write( "\"x=%28-6%29%2F2=-3\"\r
\n" ); document.write( "\n" ); document.write( "---\r
\n" ); document.write( "\n" ); document.write( "We are given two equations:\r
\n" ); document.write( "\n" ); document.write( "Equation 1:\"3x%2B4y=1\"
\n" ); document.write( "Equation 2:\"x%2B4y=7\"\r
\n" ); document.write( "\n" ); document.write( "Subtracting Equation 2 from Equation 1, we obtain:
\n" ); document.write( "\"%283x%2B4y%29-%28x%2B4y%29=1-7=-6\"
\n" ); document.write( "\"2x=-6\"
\n" ); document.write( "\"x=%28-6%29%2F2=-3\"\r
\n" ); document.write( "\n" ); document.write( "Then, substitute \"x=-3\" into Equation 2:
\n" ); document.write( "\"-3%2B4y=7\"
\n" ); document.write( "\"4y=7%2B3=10\"
\n" ); document.write( "\"y=10%2F4=5%2F2\"\r
\n" ); document.write( "\n" ); document.write( "Since \"x=-3\" and \"y=5%2F2\", the solutions of (\"x\",\"y\") are (\"-3\",\"5%2F2\"), and the answer is \"D\".
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