document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=129117>Question 129117</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A water main for a street is being laid using particular kind of pipe that comes in either 18-foot sections or 20-foot sections. The designer has determined that the water main would require 14 fewer sections of 20-foot pipe than if 18-foot sections were used. Find the total length of the water main.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #94387 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=94387\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be the number of sections of 18' pipe.<BR>\n" );
document.write( "main length=pipe length * number of sections of pipe<BR>\n" );
document.write( "20(x-14)=18x<BR>\n" );
document.write( "20x-280=18x<BR>\n" );
document.write( "20x-18x-280+280=18x-18x+280<BR>\n" );
document.write( "2x=280<BR>\n" );
document.write( "2x/2=280/2<BR>\n" );
document.write( "x=140<BR>\n" );
document.write( "18*140=2520' Length of main.<BR>\n" );
document.write( "Check:<BR>\n" );
document.write( "20(140-14)=20*126=2520<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed\r<BR>\n" );
document.write( "<BR>\n" );
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document.write( " </SPAN>\n" );
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