document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=129102>Question 129102</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of three numbers is 98. The first number is 2/3 of the second, and the second is 5/8 of the third. What is the second number? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #94371 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=94371\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x+y+z=98<BR>\n" );
document.write( "x=2y/3<BR>\n" );
document.write( "y=5z/8 or 5z=8y or z=8y/5<BR>\n" );
document.write( "2y/3+y+8y/5=98<BR>\n" );
document.write( "(5*2y+15y+3*8y)/15=98<BR>\n" );
document.write( "(10y+15y+24y)/15=98 now cross multiply<BR>\n" );
document.write( "49y=15*98<BR>\n" );
document.write( "49y=1470<BR>\n" );
document.write( "y=1470/49<BR>\n" );
document.write( "y=30 the second number.<BR>\n" );
document.write( "x=2*30/3=60/3=20 for the first number.<BR>\n" );
document.write( "30+20+z=98<BR>\n" );
document.write( "50+z=98<BR>\n" );
document.write( "z=98-50<BR>\n" );
document.write( "z=48 the third number.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );