document.write( "Question 129035: I have 2 problems that I am stumped on
\n" ); document.write( "x^2-xy/y times y^2/2x-2y how do I cancel the GCF
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\n" ); document.write( "[(x^2-xy)/y]*[y^2/(2x-2y)]
\n" ); document.write( "[x(x-y)/y]*[y^2/2(x-y)] now cancel out the (x-y) & one of the y terms.
\n" ); document.write( "x*y/2=xy/2 answer.\r
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Algebra.Com's Answer #94341 by checkley71(8403)\"\" \"About 
You can put this solution on YOUR website!
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