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document.write( "the length of a rectangle is 5 cm less than twice the width. the area is 88 cm squared. find the length and width. \n" );
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Algebra.Com's Answer #94335 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! L=2W-5 \n" ); document.write( "L*W=88 \n" ); document.write( "(2W-5)W=88 \n" ); document.write( "2W^2-5W-88=0 \n" ); document.write( "(2W+11)(W-8)=0 \n" ); document.write( "W-8=0 \n" ); document.write( "W=8 ANSWER FOR THE WIDTH. \n" ); document.write( "L=2*8-5 \n" ); document.write( "L=16-5 \n" ); document.write( "L=11 FOR THE LENGTH. \n" ); document.write( "PROOF: \n" ); document.write( "2*11-5=22-5=17 \n" ); document.write( "8*11=88 \n" ); document.write( "88=88\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |