document.write( "Question 129024: this problem starts\r
\n" ); document.write( "\n" ); document.write( "the length of a rectangle is 5 cm less than twice the width. the area is 88 cm squared. find the length and width.
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Algebra.Com's Answer #94335 by checkley71(8403)\"\" \"About 
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L=2W-5
\n" ); document.write( "L*W=88
\n" ); document.write( "(2W-5)W=88
\n" ); document.write( "2W^2-5W-88=0
\n" ); document.write( "(2W+11)(W-8)=0
\n" ); document.write( "W-8=0
\n" ); document.write( "W=8 ANSWER FOR THE WIDTH.
\n" ); document.write( "L=2*8-5
\n" ); document.write( "L=16-5
\n" ); document.write( "L=11 FOR THE LENGTH.
\n" ); document.write( "PROOF:
\n" ); document.write( "2*11-5=22-5=17
\n" ); document.write( "8*11=88
\n" ); document.write( "88=88\r
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