document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=129026>Question 129026</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The area of a rectangle is 200 sq cm and one dimension is 25 cm. Find the length of a diagonal of the rectangle (to the nearest whole number). </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #94331 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=94331\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 25x=200<BR>\n" );
document.write( "x=200/25<BR>\n" );
document.write( "x=8 for the other dimention of the rectangle.<BR>\n" );
document.write( "Now you have a right triangle with sides of 25 & 8.<BR>\n" );
document.write( "So we find the hypotenuse (diagonal) using the pythagorean equation.<BR>\n" );
document.write( "a^2+b^2=c^2<BR>\n" );
document.write( "8^2+25^2=h^2<BR>\n" );
document.write( "64+625=h^2<BR>\n" );
document.write( "689=h^2<BR>\n" );
document.write( "h=sqrt689<BR>\n" );
document.write( "h=26 cm is the length of the hypotenuse (diagonal). </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );