document.write( "Question 128995: I don't understand this problem can someone please help me. The area of a rectangle is 45 square cm. If the length is 4 cm greater than the width, what are the dimensions of the rectangle?.
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Algebra.Com's Answer #94329 by oscargut(2103)![]() ![]() You can put this solution on YOUR website! you have to find the length and the width of the rectangle \n" ); document.write( "let denotate L=length and W=width\r \n" ); document.write( "\n" ); document.write( "L=W+4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "area = L*W =45 then (W+4)W=45 then W^2+4W-45=0 \n" ); document.write( "then \n" ); document.write( "= \n" ); document.write( "= \n" ); document.write( "= \n" ); document.write( "solutions are W=-9 and W=5 then W=5\r \n" ); document.write( "\n" ); document.write( "then W=5 and L=9 \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |