document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=129014>Question 129014</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A real estate agency wishes to double the size of its ad area in a telephone<BR>\n" );
document.write( "directory by adding the same amount of length and width of the current ad.<BR>\n" );
document.write( "The current ad is 4 cm wide by 6 cm long. What will be the dimensions of the new<BR>\n" );
document.write( "ad. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #94325 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=94325\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> AREA=L*W<BR>\n" );
document.write( "AREA=4*6=24 CM^2<BR>\n" );
document.write( "TO DOUBLE THE SIZE OF THE ADD YOU NEED TO ADD 2X TO EACH DIMENSION.<BR>\n" );
document.write( "(4+2X)(6+2X)=2*24<BR>\n" );
document.write( "24+20X+4X^2=48<BR>\n" );
document.write( "4X^2+20X+24-48=0<BR>\n" );
document.write( "4X^2+20X-24=0<BR>\n" );
document.write( "4(X^2+5-6)=0<BR>\n" );
document.write( "4(X+6)(X-1)=0<BR>\n" );
document.write( "X-1=0<BR>\n" );
document.write( "X=1 THE ANSWER FOR THE INCREASED WIDTH & LENGTH OF THE AD.<BR>\n" );
document.write( "WIDTH=4+(2*1)=4+2=6<BR>\n" );
document.write( "LENGTH=6+2*1)=6+2=8<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "6*8=2*24<BR>\n" );
document.write( "48=48<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );