document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=128988>Question 128988</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A kid has 3 times more money than another . If the first one spends 2/7 of his sum of money and the second one spends 3/5 of his sum of money.So, the first kid will have 122 $ more than the second one.Find the sum of money that each had at the begining . </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #94322 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=94322\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> LET X=THE AMOOUNT OF MONEY FOR THE FIRST KID.<BR>\n" );
document.write( "LET 3X=THE AMOUNT OF MONEY FOR THE SECOND KID.<BR>\n" );
document.write( "IF THE FIRST KID SPENDS 2/7 THEN HE HAS 5*3X/7 LEFT.<BR>\n" );
document.write( "THE SECOND KIS SPENDS 3/5 THEN HE HAS 2X/5 LEFT.<BR>\n" );
document.write( "5*3x/7=2x/5+122<BR>\n" );
document.write( "15x/7-2x/5=122<BR>\n" );
document.write( "(5*15x)+7*-2x)/7*5=122<BR>\n" );
document.write( "75x-14x/35=122<BR>\n" );
document.write( "61x=35*122<BR>\n" );
document.write( "61x=4270<BR>\n" );
document.write( "x=4270/61<BR>\n" );
document.write( "x=70 for the amount of the second kid. <BR>\n" );
document.write( "3*70=210 for the first kid.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "15*70/7=2*70/5+122<BR>\n" );
document.write( "15*10=140/5+122<BR>\n" );
document.write( "150=28+122<BR>\n" );
document.write( "150=150<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );