document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=128983>Question 128983</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A worker can finish a job in 18 days.An other worker can do the same work but in 24 days and an other worker can do the same work in 30 days . If the 3 workers work 6 days together,what part of the job will be done ??<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #94321 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=94321\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "Let x=part of job that will be done with all three working together for 6 days<BR>\n" );
document.write( "Worker #1 works at the rate of 1/18 of the job per day or 6/18 of the job in 6 days<BR>\n" );
document.write( "Worker #2 works at the rate of 1/24 of the job per day or 6/24 of the job in 6 days<BR>\n" );
document.write( "Worker #3 works at the rate of 1/30 of the job per day or 6/30 of the job in 6 days\r<BR>\n" );
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document.write( "So together they do:<BR>\n" );
document.write( "6/18+6/24+6/30 of the job in 6 days and this equals:\r<BR>\n" );
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document.write( "1/3+1/4+1/5 =20/60+15/60+12/60 =x=<BR>\n" );
document.write( "47/60 of the job in 6 days\r<BR>\n" );
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document.write( "Hope this helps---ptaylor </SPAN>\n" );
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