document.write( "Question 19522: I am really suffering in this class.The problem is y=3x+6
\n" ); document.write( "y=2x+1 where do I begin to work this problem? I'm not sure of the steps.
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Algebra.Com's Answer #9432 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
You can solve this system of equations by subtracting the second equation (y = 2x+1) from the first equation (y = 3x+6) and solving for x.\r
\n" ); document.write( "\n" ); document.write( "y = 3x+6
\n" ); document.write( "-(y = 2x+1)\r
\n" ); document.write( "\n" ); document.write( "0 = x + 5 Subtract 5 from both sides.
\n" ); document.write( "x = -5 Now substitute this value of x into either of the two equations and solve for y. Take the first equation.\r
\n" ); document.write( "\n" ); document.write( "y = 3(-5)+6
\n" ); document.write( "y = -15+6
\n" ); document.write( "y = -9\r
\n" ); document.write( "\n" ); document.write( "The solution is: (-5, -9) This is the point at which the two lines, represented by the two linear equations, intersect.\r
\n" ); document.write( "\n" ); document.write( "Here's the graph:\r
\n" ); document.write( "\n" ); document.write( "\"graph%28300%2C200%2C-10%2C10%2C-15%2C10%2C3x%2B6%2C2x%2B1%29\"\r
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