document.write( "Question 128935This question is from textbook
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\n" ); document.write( "\n" ); document.write( "Stellas catering is planning a wedding reception. The bride and groom would like to serve a nut mixture containing 25% peanuts. Stella has available mixtures that are either 40% or 10% peanuts. How much of each type should be mixed to get a 10lb mixture that is 25% peanuts?
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Algebra.Com's Answer #94298 by checkley71(8403)\"\" \"About 
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.4X+.10(10-X)=.25*10
\n" ); document.write( ".4X+1-.10X=2.5
\n" ); document.write( ".3X=2.5-1
\n" ); document.write( ".3X=1.5
\n" ); document.write( "X=1.5/.3
\n" ); document.write( "X=5 POUNDS OF 40% MIX & 5 POUNDS OF 10% MIX.
\n" ); document.write( "PROOF:
\n" ); document.write( ".4*5+.10*5=.25*10
\n" ); document.write( "2+.5=2.5
\n" ); document.write( "2.5=2.5
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