document.write( "Question 128935This question is from textbook
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document.write( "Stellas catering is planning a wedding reception. The bride and groom would like to serve a nut mixture containing 25% peanuts. Stella has available mixtures that are either 40% or 10% peanuts. How much of each type should be mixed to get a 10lb mixture that is 25% peanuts? \n" );
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Algebra.Com's Answer #94298 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! .4X+.10(10-X)=.25*10 \n" ); document.write( ".4X+1-.10X=2.5 \n" ); document.write( ".3X=2.5-1 \n" ); document.write( ".3X=1.5 \n" ); document.write( "X=1.5/.3 \n" ); document.write( "X=5 POUNDS OF 40% MIX & 5 POUNDS OF 10% MIX. \n" ); document.write( "PROOF: \n" ); document.write( ".4*5+.10*5=.25*10 \n" ); document.write( "2+.5=2.5 \n" ); document.write( "2.5=2.5 \n" ); document.write( " \n" ); document.write( " |