document.write( "Question 128912: Two students have 920$ altogether. How much does each have if 5/7 of the money of the first one is equal to 3/5 of the money of the second student?\r
\n" ); document.write( "\n" ); document.write( "Please help !!
\n" ); document.write( "

Algebra.Com's Answer #94297 by checkley71(8403)\"\" \"About 
You can put this solution on YOUR website!
(5/7)X=(3/5)(920-X)
\n" ); document.write( "5X/7=(2760-3X)/5 CROSS MULTIPLY.
\n" ); document.write( "5*5X=7(2760-3X)
\n" ); document.write( "25X=19320-21X
\n" ); document.write( "25X+21X=19320
\n" ); document.write( "46X=19320
\n" ); document.write( "X=19320/46
\n" ); document.write( "X=420 ANSWER FOR THE AMOUNT FOR THE FIRST STUDENT.
\n" ); document.write( "920-420=500 FOR THE SECOND STUDENT.
\n" ); document.write( "PROOF:
\n" ); document.write( "5*420/7=3*500/5
\n" ); document.write( "2100/7=1500/5
\n" ); document.write( "300=300\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );