document.write( "Question 128912: Two students have 920$ altogether. How much does each have if 5/7 of the money of the first one is equal to 3/5 of the money of the second student?\r
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document.write( "Please help !! \n" );
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Algebra.Com's Answer #94297 by checkley71(8403) ![]() You can put this solution on YOUR website! (5/7)X=(3/5)(920-X) \n" ); document.write( "5X/7=(2760-3X)/5 CROSS MULTIPLY. \n" ); document.write( "5*5X=7(2760-3X) \n" ); document.write( "25X=19320-21X \n" ); document.write( "25X+21X=19320 \n" ); document.write( "46X=19320 \n" ); document.write( "X=19320/46 \n" ); document.write( "X=420 ANSWER FOR THE AMOUNT FOR THE FIRST STUDENT. \n" ); document.write( "920-420=500 FOR THE SECOND STUDENT. \n" ); document.write( "PROOF: \n" ); document.write( "5*420/7=3*500/5 \n" ); document.write( "2100/7=1500/5 \n" ); document.write( "300=300\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |