document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=128914>Question 128914</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A worker can do a work in 18 days . An oher worker can do the same work but in 24 days ,and another in 30 days . If the 3 workers work 6 days altogether what part of the work will be done ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #94293 by </B><A HREF=/tutors/aboutme.mpl?userid=oscargut><B>oscargut(2103)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oscargut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=oscargut><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=94293\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The first worker in 6 days does 6/18 =1/3 of the work<BR>\n" );
document.write( "The second worker in 6 days does 6/24 =1/4 of the work<BR>\n" );
document.write( "The third worker in 6 days does 6/30 =1/5 of the work\r<BR>\n" );
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document.write( "so altogether can do 1/3+1/4+1/5 of the work<BR>\n" );
document.write( "note that  1/3+1/4+1/5 = (20+15+12)/60 = 27/60 = 9/20\r<BR>\n" );
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document.write( "R: 9/20 of the work<BR>\n" );
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