document.write( "Question 128885: diaz is 1 year more than 3 times as old as his daughter. 4 years from now he will lack 7 years from being 3 times as old as his daughter is then. find each age. this is what i have tried, with the daughter being x she is x now and x plus 4 then he is 1 plus 3x now and 4 plus 1 plus 3x then - so... 1 plus 3x equals x now and 4 plus 1 plus 3x equals x plus 4 then. i think the answer comes out to be 31 and 10, but don't know if this is the right way to get there. am i close?? thank you so much for the help!! \n" ); document.write( "
Algebra.Com's Answer #94265 by stanbon(75887)\"\" \"About 
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diaz is 1 year more than 3 times as old as his daughter.
\n" ); document.write( "NOW DATA:
\n" ); document.write( "Let her daughter's age be \"x\" yrs. old
\n" ); document.write( "Diaz's age is \"3x+1\" yrs. old.
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\n" ); document.write( "4 yrs. from NOW DATA:
\n" ); document.write( "Daughter will be \"x+4\" yrs.old
\n" ); document.write( "Diaz will be 3x+1+4 = \"3x+5\" yrs old.
\n" ); document.write( "-------------------------------------------
\n" ); document.write( "4 years from now he will lack 7 years from being 3 times as old as his daughter is then. find each age.
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\n" ); document.write( "EQUATION:
\n" ); document.write( "3x+5+7 = 3(x+4)
\n" ); document.write( "3x+12 = 3x+12
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\n" ); document.write( "It looks like Diaz's daughter could be any age
\n" ); document.write( "and Diaz will be 3 times that + 1 yr.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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