document.write( "Question 128840: I need help with solving this, the equation for x\r
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document.write( "logx 1/64=-3 \n" );
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Algebra.Com's Answer #94234 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! I suspect you mean \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Remember that \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So for your problem, the base is x, the exponent is -3, and the result of raising x to the -3 power is \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "But remember that \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "And since the cube root of 64 is 4,\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " |