document.write( "Question 128844: Hi
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document.write( "I am stuck on this one which has me completely bamboozled. Your assistance would be greatly appreciated.
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document.write( "I am asked to Sol;ve the following equation for the variable given, and to write my answer with 3 significant figures.
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document.write( "The equation is as follows:
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document.write( "2y/5=3/5+2/y
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document.write( "So far this is as far as I have been able to go and I started like this.
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document.write( "2y/5=3/5+2/y
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document.write( "Then
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document.write( "2y/5=2/y+3/5
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document.write( "Then
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document.write( "2y/5-2/y-3/5=0
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document.write( "But I now do not know where to go from here. I have looked at the general quadratic equation ax^2+bx+c=0, but cannot work out which is the a, b or c. Again I have also looked at the x=-b+or-sqrt b^2-4ac/2a, but cannot see where to find the a, b or c.
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document.write( "Your help would really be appreciated. Thank you.
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document.write( "Cheers D. \n" );
document.write( "
Algebra.Com's Answer #94231 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 2y/5=3/5+2/y \n" ); document.write( "------- \n" ); document.write( "Multiply thru by 5y to get: \n" ); document.write( "2y^2 = 3y + 10 \n" ); document.write( "2y^2-3y-10 = 0 \n" ); document.write( "y = [3 +- sqrt(9-4*2*-10)]/4 \n" ); document.write( "y = [3 +- sqrt(89)]/4 \n" ); document.write( "y = (3+sqrt(89))/4 or x = (3-sqrt(89))/4 \n" ); document.write( "====================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |