document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=128813>Question 128813</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In a right triangle , the shorter leg is 6 less than the longer leg. The hypotenuse is 6 less than twice the shorter leg. Set up a quadratic equation and use it to determine the lenghth of the hypotenuse of the right triangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #94218 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=94218\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> X^2+(X-6)^2=[2(X-6)-6]^2<BR>\n" );
document.write( "X^2+X^2-12X+36=[2X-12-6]^2<BR>\n" );
document.write( "2X^2-12X+36=(2X-18)^2<BR>\n" );
document.write( "2X^2-12X+36=4X^2-72X+324<BR>\n" );
document.write( "2X^2-4X^2-12X+72X+36-324=0<BR>\n" );
document.write( "-2X^2+60X-288=0<BR>\n" );
document.write( "-2(X^2-30X+144)=0<BR>\n" );
document.write( "-2(X-6)(X-24)=0<BR>\n" );
document.write( "X-24=0<BR>\n" );
document.write( "X=24 ANSWER FOR THE LONGER LEG.<BR>\n" );
document.write( "24-6=18 IS FOR THE SHORTER LEG<BR>\n" );
document.write( "18^2+24^2=H^2<BR>\n" );
document.write( "324+576=H^2<BR>\n" );
document.write( "H^2=900<BR>\n" );
document.write( "H=SQRT900<BR>\n" );
document.write( "H=30 FOR THE HYPOTENUSE. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );