document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=128783>Question 128783</A>: <I><SPAN STYLE=\"word-break: break-all;\"> HELP ME SOLVE THIS :\r<BR>\n" );
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document.write( "90-3/2N=30 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #94211 by </B><A HREF=/tutors/aboutme.mpl?userid=MarisaLeigh><B>MarisaLeigh(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MarisaLeigh><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=94211\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 90 - (3-2N)= 30 \r<BR>\n" );
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document.write( "multiply both sides by (2N/1) to get 180N-3=60N\r<BR>\n" );
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document.write( "that means that 120N=3  and N=3/120= 1/40 </SPAN>\n" );
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