document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=128784>Question 128784</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help understanding how to simplify expressions using fractions. I am not understanding the first step I need to do. Here is an example problem:\r<BR>\n" );
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document.write( "1/2(3a-8)+1/3(2a-9)<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #94206 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=94206\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> IF YOU MEAN<BR>\n" );
document.write( "(3A-8)/2+(2A-9)/3 THEN:<BR>\n" );
document.write( "COMBINING THESE FRACTIONS BY FINDING A COMMON DENOMINATOR (6) WE GET:<BR>\n" );
document.write( "[3(3A-8)+2(2A-9)]/(2*3)<BR>\n" );
document.write( "(9A-24+4A-18)/6<BR>\n" );
document.write( "(13A-42)/6<BR>\n" );
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