document.write( "Question 128713: i am having a very hard time grasping this concept
\n" ); document.write( "differentiate two ways: the product rule and then by multiplying the expression before differentiating. can you help me sto solve this problem step by step? thanks in advance\r
\n" ); document.write( "\n" ); document.write( "g(x)=(4x-3)(2x^2+3x+5)
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Algebra.Com's Answer #94179 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Differentiate by the product rule and then by multiplying then differentiating:
\n" ); document.write( "\"g%28x%29+=+%284x-3%29%282x%5E2%2B3x%2B5%29\"
\n" ); document.write( "First, let \"u+=+%284x-3%29\" and \"v+=+%282x%5E2%2B3x%2B5%29\"
\n" ); document.write( "The product rule is:
\n" ); document.write( "\"dy%2Fdx+=+u%2A%28dv%2Fdx%29+%2B+v%2A%28du%2Fdx%29\" Applying this to your problem:
\n" ); document.write( " Applying the differentiation:
\n" ); document.write( "\"dg%2Fdx+=+%284x-3%29%284x%2B3%29%2B%282x%5E2%2B3x%2B5%29%284%29\" Simplify:
\n" ); document.write( "\"dg%2Fdx+=+16x%5E2%2B12x-12x-9%2B8x%5E2%2B12x%2B20\"
\n" ); document.write( "\"dg%2Fdx+=+24x%5E2%2B12x%2B11\"
\n" ); document.write( "Now we'll multiply then differentiate:
\n" ); document.write( "\"%284x-3%29%282x%5E2%2B3x%2B5%29+=+8x%5E3%2B12x%5E2%2B20x-6x%5E2-9x-15\" Simplifying, we get:
\n" ); document.write( "\"g%28x%29+=+8x%5E3%2B6x%5E2%2B11x-15\" Now we'll differentiate:
\n" ); document.write( "\"dg%2Fdx+=+24x%5E2%2B12x%2B11\"
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