document.write( "Question 19411: When two resistors S and T are connected in parallel their combined resistance R is given by the expression \r
\n" ); document.write( "\n" ); document.write( " R=1/((1/S)+(1/T))
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\n" ); document.write( "\n" ); document.write( "This expression can be rewritten as a rational expression in S and T. The numerator of that expression is ST and its denominator is S+T \r
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\n" ); document.write( "\n" ); document.write( "Suppose you connect two resistors of the same resistance in parallel. Then the resistance of the two connected resistors equals _________ times that of each resistor alone. \r
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Algebra.Com's Answer #9415 by xcentaur(357) $\"\"$ $\"About$

You can put this solution on YOUR website!
R=ST/(S+T)
\n" ); document.write( "Now if they have the same value,S=T
\n" ); document.write( "R=T*T(T+T)=(T^2/2T)
\n" ); document.write( "So the resistance would be (T^2/2T)
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\n" ); document.write( "To find how many times it is greater than T alone,find the ratio:
\n" ); document.write( "Let the ratio be x
\n" ); document.write( " $\"%28%28T%5E2%2F2T%29%29%2FT=x\"$
\n" ); document.write( " $\"%28T%5E2%2F2T%29%2A%281%2FT%29=x\"$
\n" ); document.write( " $\"%28T%5E2%2F2T%5E2%29=x\"$
\n" ); document.write( " $\"1%2F2=x\"$
\n" ); document.write( "therefore our ratio is (1/2)
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\n" ); document.write( "Thats your answer.
\n" ); document.write( "Hope this helps,
\n" ); document.write( "Prabhat \n" ); document.write( "

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