document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=19404>Question 19404</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the measure of an angle whose supplement measures 38 degrees less than three times its complement. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #9414 by </B><A HREF=/tutors/aboutme.mpl?userid=xcentaur><B>xcentaur(357)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=xcentaur><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=9414\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the angle be x<BR>\n" );
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document.write( "its complement=(90-x)<BR>\n" );
document.write( "its supplement=(180-x)<BR>\n" );
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document.write( "acc to the question,<BR>\n" );
document.write( "(supplement)+38=3(complement)<BR>\n" );
document.write( "(108-x)+38=3(90-x)<BR>\n" );
document.write( "108+38-x=270-3x<BR>\n" );
document.write( "146=270-3x+x<BR>\n" );
document.write( "146-270=-3x+x<BR>\n" );
document.write( "-124=-2x<BR>\n" );
document.write( "124=2x<BR>\n" );
document.write( "2x=124<BR>\n" );
document.write( "x=62<BR>\n" );
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document.write( "Hope this helps,<BR>\n" );
document.write( "Prabhat </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );