document.write( "Question 19478: Please help me with this problem I have exhausted all of my resources to try and figure it out.\r
\n" ); document.write( "\n" ); document.write( "On a windy day Yoshiaki found that he could go 16mi downstream and then 4mi back upstream at top speed in a total of 48min. What was the top speed of Yoshiaki's boat if the current was 15mph?
\n" ); document.write( "
\n" ); document.write( "The answer in the back of the book is 25mph, but I can't seem to figure out how they came up with that answer. We are working with quadratic equations. Here is what I have tried:
\n" ); document.write( "______________D_____R________T_______
\n" ); document.write( "upstream:_____4mi___x-15___4/(x-15)
\n" ); document.write( "downstream:___16mi__x+15___16/(x+15)
\n" ); document.write( "_____________________________________
\n" ); document.write( "4/(x-15) + 16/(x+15) = 48 \r
\n" ); document.write( "\n" ); document.write( "I cannot seem to come up with the answer 25, I must be doing something wrong in the form of the equation. Please Help!!
\n" ); document.write( "

Algebra.Com's Answer #9410 by xcentaur(357)\"\" \"About 
You can put this solution on YOUR website!
Let the speed of the boat be x mph
\n" ); document.write( "let the speed of the current be y mph
\n" ); document.write( "


\n" ); document.write( "Then while going downstream,
\n" ); document.write( "distance downstream=16miles
\n" ); document.write( "speed=(x+y) [since the current helps the boat]
\n" ); document.write( "time taken=d/s=16/(x+y).......[1]
\n" ); document.write( "


\n" ); document.write( "while going upstream,
\n" ); document.write( "distance upstream=4 miles
\n" ); document.write( "speed=(x-y) [since the current is in the opposite direction of the boat]
\n" ); document.write( "time taken=d/s=4/(x-y).........[2]
\n" ); document.write( "


\n" ); document.write( "Now we have been told that the total time taken is 48 minutes
\n" ); document.write( "48 minutes means : (48/60)hour=(4/5)hour
\n" ); document.write( "


\n" ); document.write( "Add up both the times we got (equations 1 and 2)
\n" ); document.write( "\"%2816%2F%28x%2By%29%29%2B%284%2F%28x-y%29%29=4%2F5\"
\n" ); document.write( "\"%2816%28x-y%29%2B4%28x%2By%29%29%2F%28%28x%2By%29%28x-y%29%29=4%2F5\"
\n" ); document.write( "\"%2816x-16y%2B4x%2B4y%29%2F%28x%5E2-y%5E2%29=4%2F5\"
\n" ); document.write( "\"%2820x-12y%29=4%2F5%28x%5E2-y%5E2%29\"
\n" ); document.write( "Now we have been told in the question that the speed of the current (y) is 15 mph
\n" ); document.write( "So we get,
\n" ); document.write( "\"%2820x-12%2815%29%29=4%2F5%28x%5E2-%2815%29%5E2%29\"
\n" ); document.write( "\"20x-180=4%2F5%28x%5E2-225%29\"
\n" ); document.write( "opening the brackets
\n" ); document.write( "\"20x-180=4%2F5x%5E2-4%2F5%28225%29\"
\n" ); document.write( "\"20x-180=4%2F5x%5E2-4%2845%29\"
\n" ); document.write( "\"20x-180=4%2F5x%5E2-180\"
\n" ); document.write( "now '-180' cancels off
\n" ); document.write( "\"20x=4%2F5x%5E2\"
\n" ); document.write( "\"100x=4x%5E2\"
\n" ); document.write( "\"25x=x%5E2\"
\n" ); document.write( "which can be written as
\n" ); document.write( "\"25x=x%2Ax\"
\n" ); document.write( "cancelling out the x we get,
\n" ); document.write( "\"25=x\"
\n" ); document.write( "\"x=25\"
\n" ); document.write( "


\n" ); document.write( "And so we get the top speed of the boat(x) = 25 mph
\n" ); document.write( "


\n" ); document.write( "Hope this helps,
\n" ); document.write( "Prabhat
\n" ); document.write( "

\n" );