document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=128616>Question 128616</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose that the length of a rectangle is 3 inches longer than the width and that the perimeter of the rectangle is 78.\r<BR>\n" );
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document.write( "A)  Set up an equation involving only W, the width of the rectangle.\r<BR>\n" );
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document.write( "B) Solve this equation algebraically to find the length of the rectangle, find the width as well.\r<BR>\n" );
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document.write( "Length =            Width =  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #94094 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=94094\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L=W+3 <BR>\n" );
document.write( "2L+2W=78<BR>\n" );
document.write( "2(W+3)+2W=78<BR>\n" );
document.write( "2W+6+2W=78<BR>\n" );
document.write( "4W=78-6<BR>\n" );
document.write( "4W=72<BR>\n" );
document.write( "W=72/4<BR>\n" );
document.write( "W=18 IS THE WIDTH.<BR>\n" );
document.write( "L=18+3=21 IS THE LENGTH.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "2*18+2*21=78<BR>\n" );
document.write( "36+42=78<BR>\n" );
document.write( "78=78 </SPAN>\n" );
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